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Rufina [12.5K]
3 years ago
12

What does this expression represent five times the quotient of some number and ten

Mathematics
2 answers:
hammer [34]3 years ago
6 0

Answer:

the answer is b

Step-by-step explanation:


Galina-37 [17]3 years ago
3 0
If we break down the problem if basically gives the answer:
five times the quotient of some number and ten
5 times (any variable) divided by 10 

The answer is B. The answer isn't A because you have to go in order of what the question states. It didn't say ten first. It can't be C or D because those are not quotients. 
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SHEILA made 5 times as many baskets
Thepotemich [5.8K]

Answer:

25

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP 10pts
Veronika [31]

Answer:

Hence the function which has the smallest minimum is: h(x)

Step-by-step explanation:

We are given function f(x) as:

  • f(x) = −4 sin(x − 0.5) + 11

We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.

so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.

Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)

  • Also we are given a table of values for function h(x) as:

x    y

−2   14

−1   9

 0   6

  1   5

 2   6

 3   9

 4   14

Hence, the minimum value attained by h(x) is 5. ( when x=1)

  • Also we are given function g(x) ; a quadratic function passing through (2,7),(3,6) and (4,7)

so, the equation will be:

g(x)=ax^2+bx+cHence on putting these coordinates we will get:

a=1,b=3 and c=7.

Hence the function g(x) is given as:

g(x)=x^2-6x+15

So,the minimum value attained by g(x) could be seen from the graph is at the point (3,6).

Hence, the minimum value attained by g(x) is 6.

Hence the function which has the smallest minimum is h(x)

6 0
3 years ago
Read 2 more answers
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
Length is to meter as
Mama L [17]
Answer:

a. mass is to kilogram.
4 0
3 years ago
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