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3 years ago

15

If f (x) - 3(x + 5) +-, what is f(a + 2)?

1 answer:

sergey [27]3 years ago

4 0

Answer:

A

Step-by-step explanation:

Just plug in $x=a+2$ .

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Test worth 75 points ; test score of 96%

vfiekz [6]

Presuming the question is "How many points did he miss", you would find the solution by multiplying the amount of possible points by the test score as a fraction. 96% is the fraction $\frac{96}{100}$ . Therefore, you get the equation $75*\frac{96}{100}$ . This is equal to 72, so he missed 3 points, or 75-72 points.

He missed 3 points.

6 0

3 years ago

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What is the image point (-2,-7) after a translation right 4 units and down 2 units

xenn [34]

Answer:

(2,-9)

Step-by-step explanation:

-2+4=2

-7-2=-9

down=negative

right=positive

left=negative

up=positive

7 0

4 years ago

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Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

Plz don’t be rude if i got brainly i’m gonna use it

SSSSS [86.1K]

Answer:

y=-5x-36

Step-by-step explanation:

-66-(-61)= -5

6-5= 1

-5/1= -5

Y=-5x + B

-66= -5(6) + B

-66= -30 + B

-66 + 30 = (-30 +30) + B

-36 = B

Y= -5x-36

4 0

3 years ago

What is equivalent to 5(8d)

kati45 [8]

Answer: ( 2 + 3 ) ( 8d )

Step-by-step explanation:

There are multiple possible answers and I'm not sure if you're missing part of the question.

Correct me if I am incorrect.

8 0

3 years ago

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