Answer:
B. y= 2x–15
Step-by-step explanation:
The equation that represents the line that passes through the points (8, 1) and (10,5) is y= 2x–15
"x" is found on the left hand side of the bracket and "y" is found on the right hand side of the bracket :)
(8, 1) and (10, 5)
x in the first bracket is 8 and x in the second bracket is 10.
y in the first bracket is 1 and y in the second bracket is 5.
When this equation is applied to find the value for y we get:
y= 2x-15
y= 2(8)-15
y= 16-15
y= 1
y= 2x-15
y= 2(10)-15
y= 20-15
y= 5
We got back the values of y and this means that the equation was correctly chosen and the answer is correct :)
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
Answer:
12:50 PM.
Step-by-step explanation:
We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.
We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.
We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.
Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.
Therefore, 4th lesson will end at 12:50 PM.