Science

1 answer:

3 0

It is volume. The density would be far greater for the books and the atoms as well probably. But volume is just the length x width x height or something.

You might be interested in

What binomial do you have to add to the polynomial 2x^2+3y^2-5xy+1 to get the following. A polynomial that does not contain x

kiruha [24]

The Binomial $-2x^{2} + 5xy$ have to be add to the polynomial $2x^{2} +3y^{2} -5xy+1$ to get polynomial that does not contain x.

<h3>What is binomial?</h3>

A mathematical expression consisting of two terms connected by a plus sign or minus sign.

Example: x + 2 is a binomial, where x and 2 are two separate terms.

<h3>What is polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer

According to question

polynomial $2x^{2} +3y^{2} -5xy+1$

When added to binomial $-2x^{2} + 5xy$

= $3y^{2} +1$ (as $2x^{2} -5xy$ got cancelled )

and this polynomial does not contain x

Hence, Binomial $-2x^{2} + 5xy$ have to be add to polynomial $2x^{2} +3y^{2} -5xy+1$ to get polynomial that does not contain x.

To know more about Binomial and polynomial here :

brainly.com/question/1698358?\

# SPJ2

4 0

2 years ago

4 pizzas cost £15. Work out the cost of 5 pizzas.

nadezda [96]

We can divide 15 by 4. This gives us 3.75. This means that each pizza costs $3.75. I can now multiply 3.75 by 5.

3.75(5) = 18.75

5 pizzas cost $18.75.

8 0

2 years ago

Read 2 more answers

N=4; 2i and 3i are zeros <br> f(-1)=50

Nonamiya [84]

Solution:- $\text{Let f(x) be any nth degree polynomial with n=4}\\$

$\text{Given that 2i and 3i are the zeroes of f(x)}$

$\text{so (x-2i) and (x-3i) are factors of f(x)}$

$\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}$

$\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)$