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Ymorist [56]
3 years ago
8

Of the 1,000 students in a local college, 420 own brand X mobile phones and 580 own brand Y mobile phones. Of these students, 80

own both brands of mobile phones. Find the probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone.
Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0
If we were to put this in terms of a venn diagram, we would have 360 owning only brand X, 500 owning only brand Y, and 80 in between, owning both. Therefore, 80 out of the 580 owners of brand Y may have X as well, which we put into fraction form 80/580, and reduce to 4/29.
-Dominant- [34]3 years ago
4 0

Answer: \dfrac{4}{29}

Step-by-step explanation:

We know that the formula to find the conditional probability of A given that B is given by :-

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Let A be the event that students own mobile phones  of Brand X and B be the event that students own mobile phones  of Brand Y.

Then , P(A)=\dfrac{420}{1000}

P(B)=\dfrac{580}{1000}

P(A|B)=\dfrac{80}{1000}

Then , the required probability will be:-

P(A|B)=\dfrac{\dfrac{80}{1000}}{\dfrac{580}{1000}}\\\\\\\Rightarrow P(A|B)=\dfrac{4}{29}

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