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3 years ago

Are the areas of two congruent figures equal? Explain. Draw a diagram to support your answer.

Mathematics

1 answer:

Citrus2011 [14]3 years ago

7 0

Okay, so I'm not doing the diagram bit, but the answer is basically yeah.

Two similar figures do NOT always have equal areas.

However, if you have two of the exact same figure, with the same lengths and everything, they will always, for a fact, have equal areas.

Hope this helps

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Given z3 = 3 + StartRoot 3 EndRoot ii, which letter represents z?

Vlada [557]

Answer:

It is A

Step-by-step explanation:

Got it right on the test :)

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What is the equation of 21 less than 11 times a number results in seven times a number decreased by 29 what is the number

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Answer:

x=-2

Step-by-step explanation:

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2 years ago

How many 0.75 pound packages can be made with 6 pounds of sunflower seeds?

Andrej [43]

If you would like to know how many 0.75 pound packages can be made with 6 pounds of sunflower seeds, you can calculate this using the following steps:

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3 years ago

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The volume of a box(V) varies directly with its length(l). Using k for the constant of proportionality, express the relationship

pochemuha

Answer: V = L (k)

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given:

Volume of a box = V
Length = l
Constant of proportionality = k

We know that the volume of the box (V) varies directly with its length (l).

So, the expression for the volume is:

V = L (k)

Feel free to ask for more if needed or if you did not understand something

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3 years ago

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan

Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917$

0.3917 = 39.17% probability that she had found someone to help

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3 years ago