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uranmaximum [27]
3 years ago
14

Solve the system of equations and choose the correct ordered pair.

Mathematics
2 answers:
Dafna1 [17]3 years ago
3 0

So for this, I will be doing the elimination method. Firstly, multiply both sides of the first equation by 2:

6x-8y=52\\2x+8y=-36

Next, add the two equations together to get 8x=16 . From here you can solve for x.

For this equation, just divide both sides by 8 and your first answer will be x=2

Now that we have the value of x, substitute it into either equation to solve for y:

3*2-4y=26\\6-4y=26\\-4y=20\\y=-5\\\\2*2+8y=-36\\4+8y=-36\\8y=-40\\y=-5

<u>In short, the solution is (2,-5), or A.</u>

slavikrds [6]3 years ago
3 0

3x-4y=26

2x+8y=-36

We will solve this system with gaus algorithm

We multiply first equation with number 2 and we get

6x-8y=52 => we add second equation to this and we get

8x=16 => x=2 => we replace x=2 in first equation and we get

3*2-4y=26 => 6-4y=26 => -4y=20 => y=-5

The correct answer is A.

Good luck!!!



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Mice21 [21]

Solution: The solution is shown is below figure.

Explanation:

From the given information JKLM is a parallelogram and \underset{LN}{\rightarrow} bisects \angle KLP. So Blank 1 is filled by Given and blank 2 is filled by \underset{LN}{\rightarrow} bisects \angle KLP.

Parallelogram is a quadrilateral  whose opposite sides are equal or parallel. Since it is given that JKLM is a parallelogram, therefore the side JM is parallel to the side KL. So blank 3 filled by Definition of parallelogram.

If a line bisects an angle it is means it divides the angle in two equal parts. Since \underset{LN}{\rightarrow} bisects \angle KLP, therefore \angle 2\cong \angle 3. Hence the blank 4 is filled by Definition of bisect.

The transitive property of congruence states that if \angle 1\cong \angle 2 and \angle 2\cong \angle 3, then \angle 1\cong \angle 3. Thus, the blank 5 is filled by Transitive Property of Congruence.

5 0
4 years ago
Solve for x <br> Picture is above
Phantasy [73]

Answer:

x = 10

Step-by-step explanation:

a² + b² = c²

6² + 8² = c²

36 + 64 = 100

√100 = ±10

x = 10

3 0
3 years ago
Read 2 more answers
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ziro4ka [17]
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6 0
3 years ago
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Each of the 10 students in the baking club made 2 chocolate cakes for a fundraiser. They all used the same recipe, using C cups
8090 [49]

Answer:

The expression is C/20 cups of flour in one cake

Step-by-step explanation:

* Lets explain how to solve the problem

- There are 10 students

- Each one made 2 chocolate cakes

- They all used the same recipe

- The total amount of flour is C cups

* Lets change these information to equation

∵ There are 10 students

∵ Each student made 2 cakes

∴ The total number of cakes = 10 × 2 = 20 cakes

∵ The total amount of flour for the twenty cakes is C cups

- To find the amount of flour in each cake divide the total amount

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∴ The amount of flour in each cake = C/20

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7 0
4 years ago
The area of a door is 3024 square inches. If the length of the door is 48 inches longer than the width of the door, what is the
borishaifa [10]

Answer:

The width of the door is 36 inches

Step-by-step explanation:

The given parameters are;

The given area of the door = 3024 in.²

The length of the door = 48 + The width of the door

Let W represent the width of the door

Therefore, we have;

The length of the door = 48 + W

The area of the door = The length of the door × The width of the door

∴ By substitution, the area of the door = 3024 = W × (48 + W)

3024 = W × (48 + W) = 48·W + W²

48·W + W² = 3024

∴ 48·W + W² - 3024 = 0

Rearranging, we get;

W² + 48·W - 3024 = 0

By trial and error, we have;

(W + 84)×(W - 36) = 0

Therefore, given that the width of the door is a natural number, we have;

The width of the door, W = 36 inches

7 0
3 years ago
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