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uranmaximum [27]
3 years ago
14

Solve the system of equations and choose the correct ordered pair.

Mathematics
2 answers:
Dafna1 [17]3 years ago
3 0

So for this, I will be doing the elimination method. Firstly, multiply both sides of the first equation by 2:

6x-8y=52\\2x+8y=-36

Next, add the two equations together to get 8x=16 . From here you can solve for x.

For this equation, just divide both sides by 8 and your first answer will be x=2

Now that we have the value of x, substitute it into either equation to solve for y:

3*2-4y=26\\6-4y=26\\-4y=20\\y=-5\\\\2*2+8y=-36\\4+8y=-36\\8y=-40\\y=-5

<u>In short, the solution is (2,-5), or A.</u>

slavikrds [6]3 years ago
3 0

3x-4y=26

2x+8y=-36

We will solve this system with gaus algorithm

We multiply first equation with number 2 and we get

6x-8y=52 => we add second equation to this and we get

8x=16 => x=2 => we replace x=2 in first equation and we get

3*2-4y=26 => 6-4y=26 => -4y=20 => y=-5

The correct answer is A.

Good luck!!!



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The hypotenuse of a right triangle is 6 cm and one side is 2 cm longer than the other side. Find the length of each side to one
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The two legs of the right triangle are approximately 3.1 cm and 5.1 cm and the hypotenuse is 6 cm.

Step-by-step explanation:

Let <em>x</em> be one leg of the right triangle.

Since the other leg is two centimeters longer, it can be represented by the expression:

x + 2 \text{ cm}

According to the Pythagorean Theorem, for a right triangle:

a^2 + b^2 = c^2

Where <em>c</em> is the hypotenuse and <em>a</em> and <em>b</em> are the two legs.

The hypotenuse is given to be 6 cm and the two legs are <em>x</em> and (<em>x</em> + 2). Hence:

(x)^2 + (x+2)^2 = 6^2

Solve for <em>x</em>. Simplify:

x^2 + (x^2 + 4x + 4) = 36

Simplify:

2x^2 + 4x + 4 = 36

Subtract:

2x^2 + 4x - 32 =0

Divide:

x^2 + 2x - 16 = 0

The equation is not factorable, so we can consider using the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2 -4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 2, and <em>c</em> = -16. Substitute:

\displaystyle x= \frac{-(2)\pm\sqrt{(2)^2-4(1)(-16)}}{2(1)}

And evaluate:

\displaystyle \begin{aligned}x &= \frac{-2\pm\sqrt{68}}{2} \\ \\ &= \frac{-2\pm\sqrt{4\cdot 17}}{2} \\ \\ &= \frac{-2\pm2\sqrt{17}}{2} \\ \\ &= -1 \pm \sqrt{17} \end{aligned}

Hence, our two solutions are:

\displaystyle x = -1 + \sqrt{17} \approx 3.1\text{ or } x = -1 - \sqrt{17} \approx -5.1

Lengths cannot be negative, so we can ignore the second solution.

Hence, the value of <em>x</em> or the first side length is about 3.1 centimeters.

Since the other side length is two centimeters longer, the other side is about 5.1 centimeters.

In conclusion, the two legs of the right triangle are approximately 3.1 cm and 5.1 cm and the hypotenuse is 6 cm.

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