Part B

AURORKA [14]

Not sure if the math is correct but I think that it is $199.5

6 0

3 years ago

In a certain soccer tournament you play 6 games. In every match you get 3 points if you win, 1 point for a draw and 0 points if

Ann [662]

Answer:

0.430625 = 0.431

Step-by-step explanation:

Let W represent winning, D represent a draw and L represent a loss.

12+ points can be garnered in each of the following ways.

6W 0D 0L

5W 1D 0L

5W 0D 1L

4W 2D 0L

4W 1D 1L

4W 0D 2L

3W 3D 0L

The probability of getting 12+ points is the sum of all these 7 probabilities.

Knowing that P(W) = 0.5

P(D) = 0.1

P(L) = 0.4

P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625

P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875

P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075

P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375

P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075

P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15

P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025

The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625

5 0

3 years ago

Tickets to the school play cost $4.00 for adults and $2.00 for students. If 85 people attend the show, and the receipts totaled

qwelly [4]

Answer:I think it is 226

Step-by-step explanation:

85/2= 42.5 then 268 - 42.5= 225.5 then round it and you get 226

6 0

4 years ago

I will mark as the brainliest answer <br><br> Please show your work

swat32

3 and 5 are the answer

4 0

3 years ago

A piece of wire of length L will be cut into two pieces, one piece to form a square and the other piece to form an equilateral t

inn [45]

Answer:

(a) square: L; triangle: 0.

(b) square: L·(-16+12√3)/11; triangle: L·(27-12√3)/11

Step-by-step explanation:

<u>Strategy</u>: First we will write each area in terms of its perimeter. Then we will find the total area in terms of the amount devoted to the square. Differentiating will give a way to find the minimum total area.

__

In terms of its perimeter p, the area of a square is ...

A_square = p^2/16

In terms of its perimeter p, the area of an equilateral triangle is ...

A_triangle = p^2/(12√3)

Then the total area of the two figures whose total perimeter is L with "x" devoted to the square is ...

A_total = x^2/16 + (L-x)^2/(12√3)

__

(a) We know when polygons are regular, the one with the most area for the least perimeter is the one with the most sides. Hence, the total area is maximized when all of the wire is devoted to the square.

__

(b) The derivative of A_total with respect to x is ...

dA/dx = x/8 -(L-x)/(6√3)

This will be zero when ...

x/8 = (L-x)/(6√3)

x(6√3) = 8L -8x

x(8 +6√3) = 8L

x = L·8/(6√3 +8) = 8L(6√3 -8)/(64-108)

x = L·(12√3 -16)/11

The total area is minimized when L·(12√3 -16)/11 is devoted to the square, and the balance is devoted to the triangle.

5 0

3 years ago