Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
1/8 or D, because 1/2 divied by 4 equals 1/8. Hope I helped! I need some help on one question for me.
Answer:
12 which is on C
Step-by-step explanation:
use pathogoras theorem
a^2+b^2=c^2
16^2+b^2=20^2
256+b^2=400
b^2=400-256
b^2=144
b= square root of 144
b= 12
The vertex and the t-intercept where t>0, will help solve this problem. Sending the work on the attachment.
Answer: a continuous random variable
Step-by-step explanation:
<u><em>Can you count the distance it traveled?</em></u> You can't, so it couldn't be discrete because you can count discrete variables.
<u><em>Can you measure the distance it traveled? </em></u>You sure can, that makes it a continuous random variable.
<u><em>Do you know the exact distance it's going to travel?</em></u><u> </u>You won't, therefore it's a random variable since you don't know the value beforehand.
