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andrezito [222]
2 years ago
10

A chicken farm produces ideally 600,000 eggs per day. But this total can vary by as many as 50,000 eggs. What is the maximum and

minimum expected production at the farm?
Mathematics
1 answer:
Alex777 [14]2 years ago
4 0

Answer:

maximum 650,000 eggs

minimum 550,000 eggs

Step-by-step explanation:

It seems that the ideal production of eggs can be lowered by 50,000 or increased by 50,000, therefore the total number can vary from

600,000 - 50,000 = 550,000 minimum

to a maximum of: 600,000 + 50,000 = 650,000

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kvv77 [185]

Answer:  y = 650(0.907)^t

This is the same as writing y = 650(0.907)^t

=====================================================

Explanation:

Exponential equations can be of the form y = a*b^t

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In this case, we have

  • a = 650 mg to start with
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If we had exponential growth, then we'd compute 1 + 0.093 instead.

Based on those values, we go from y = a*b^t to y = 650(0.907)^t which is the same as writing y = 650(0.907)^t

Other exponential forms are possible, but I think this form is the most intuitive. The 0.907 means that 90.7% of the sample remains after each year.

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(21.5-4)/2.5=amount of rides

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