Question

1.3. If Sara draws a red ball and DOES NOT RETURN it, and then she goes to draw a green

Answer 1

Answer:

Dependent Event

Step-by-step explanation:

Assume that are 10 balls, such that:

$Red = 6$

$Green = 4$

If the balls are replaced after taken, the probability is:

$Pr(Red) = 6/10$

$Pr(Green) = 4/10$

This is referred to as independent event; because each selection do not affect the next or previous selection

However, if the balls are not replaced, the probability is:

$Pr(Red) = 6/10$

$Pr(Green) = 5/(10 - 1) = 5/9$

We subtracted 1 because there is a reduction in the number of balls when the red ball is not returned.

This is referred to as independent event; because a selection affects the next selection