Answer:
(3,0.5)
Step-by-step explanation:
The given system has equations:
Let us multiply the second equation by 4 and the first equation by 10.
We add both new equations to get:
Put x=3 into the first equation and solve for y.
The point of intersection is the solution to the system of equation which is (3,0.5)
Answer:
140 units²
Step-by-step explanation:
1/2bh=
1/2(15-5)(30-2)=
1/2 (10)(28)=140
Sorry I don’t know the answer hope you find one bye
Answer: x = 0 y = –3
Step-by-step explanation:
We can solve this system by substitution.
use the second equation as a value for x.
Then substitute that value in place of x in the first equation and solve for y.
6x - 5y = 15 becomes
6(y + 3) - 5y = 15 Distribute 6 × parentheses
6y + 18 - 5y = 15 combine like terms
6y -5y + 18 = 15
y + 18 = 15 Subtract 18 from both sides.
y =15 -18
y = –3
Use this value for y in either equation to solve for x
6x - 5(-3) = 15
6x + 15 = 15 Subtract 15 from both sides, divide by 6 (seems silly!)
x = 0
OR in he second equation,
x = -3 + 3
Again, x = 0
Answer:
D. (25π - 50) sq m
Step-by-step explanation:
Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.
I hope this helped! :D
