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Kitty [74]
3 years ago
6

You had $23 to spend on eight raffle tickets. After buying them you had $7. How much did each raffle ticketcost?

Mathematics
2 answers:
Dovator [93]3 years ago
8 0
23 - 7 = 16
16/8 = 2
each raffle ticket cost $2
Harman [31]3 years ago
4 0
You had $23. After you bought, you had $7. 

Subtract 7 from 23 to find the total amount you spent

23 - 7 = 16

You spent $16 on 8 tickets.

Divide 16 by 8 to find the price of 1 ticket.

16 ÷ 8 = 2

Each raffle ticket costs $2

Hope this helps :)
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The coordinates of the vertices of a polygon are shown below
kakasveta [241]

Answer:

Option D.

Step-by-step explanation:

The given vertices of a polygon are D(-4,5),E(-1,5),F(1,2), and G(-1,-1).

Here, number of vertices is 4.

In heptagon, number of vertices = 7

In hexagon, number of vertices = 6

In octagon, number of vertices = 8

In quadrilateral, number of vertices = 4

Since the given polygon has 4 vertices, therefore it is a quadrilateral.

Hence, option D is correct.

8 0
4 years ago
A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of
finlep [7]

Answer:

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

p_v =2*P(t_{(7)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=0.475

The sample deviation calculated s=0.183

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 0.5  

Alternative hypothesis:\mu \neq 0.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=8-1=7  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(7)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

4 0
3 years ago
Read 2 more answers
If angle m=25 and angle l=25 find jkm
suter [353]

Answer:

130

Step-by-step explanation:

25+25 = 50

180-50=130

4 0
4 years ago
Read 2 more answers
You roll two dice. What is the probability that the sum of the dice is greater than 7 and one dice shows a 2? A 6x6 table of dic
vesna_86 [32]
In this question, the condition asked is two which was
1. The dice sum >7 (notice that >7 mean at least 8)
2. One of the two dice show a 2

It will be easier to fulfill the No.2 condition first so you can divide the probability into two,
Case 1: 1st dice show 2: then the second dice need to be 6 to made it sum>7
Case 2:2nd dice show 2: then the second dice need to be 6 to made it sum>7

The probability for a dice showing 2 is 1/6. The probability for a dice showing 6 is 1/6. Then the probability is 1/6 * 1/6= 1/36 for each case
Since case 1 and case 2 has same probability, then you just need to multiply 1/36 *2 = 1/18
5 0
4 years ago
I WILL GIVE BRAINLIST IF THE ANSWER IS RIGHT
SSSSS [86.1K]

Answer:

Pair of terms

Step-by-step explanation:

8 0
3 years ago
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