Answer:
-3
3x/(x^2+6x) = 1 is this the qstn?
if so then the ans is -3
Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is defined as



Answer:
x=3
y=5
Step-by-step explanation:
x+5y=28 (i)
-x-2y=-13. (ii)
add equation 2 from equation 1
x+5y=28
-x-2y=-13
3y=15
y=5
put the value of y in equation 1
x+5y=28
x+5*5=28
x+25=28
x=28-25
x=3
Answer:
60?
Step-by-step explanation:
4000/200 = 20
20 × 3 =60