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Lana71 [14]
3 years ago
12

How many seven digit telephone numbers are possible the first digit cannot be three and the number must be a multiple of 10

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

900,000.

Step-by-step explanation:

If the number is a multiple of 10 it must end in zero.

The first digit can be any one of 0-9 except 3 - that is one of 9 digits.

All other positions (2nd to 6th) can be any one of 0 to 9 (10 digits).

So the number of possible telephone numbers is:

9*10*10*10*10*10

= 900,000.

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You first need to isolate the y
4x+9y=-108
9y=-4x-108 (subtract 4x from both sides)
y=-4/9x-12 (divide both sides by 9)
Then, by using the y=mx+b form, we can tell that the y-intercept is -12 so A

Hope this helps
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3 years ago
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Answer:

B.

Step-by-step explanation:

Because if you look closely you will be able to tell which answer it is by looking at the way the shape formed andjust breakaprt the shape .

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A quadrilateral PQRS is inscribed in a circle, A quadrilateral PQRS is inscribed in a circle. The measure of angle PQR is 85 deg
sasho [114]

Answer:

Measure of arc PQR is 190°

Step-by-step explanation:

First have a sketch of the quadrilateral PQRS inside a circle

You should notice that the intercepted angle is ∠PSR

You should remember that the intercepted arc PQR is twice the intercepted angle ∠PSR

Find the intercepted angle ∠PSR

Remember that in a quadrilateral opposite angles add up to 180°

Hence;

∠PQR+∠PSR=180°

85 + ∠PSR=180°

∠PSR=180°-85°=95°

Find arc PQR

Arc PQR =2×∠PSR

Arc PQR=2×95°

=190°

3 0
3 years ago
100 POINTS please show your work
Anon25 [30]

Answer:

See below for answers and explanations (along with a graph)

Step-by-step explanation:

<u>Part A</u>

Set f(x)=0 and factor the expression by grouping:

f(x)=2x^2-3x-5\\\\0=2x^2-3x-5\\\\0=2x^2+2x-5x-5\\\\0=2x(x+1)-5(x+1)\\\\0=(2x-5)(x+1)

Use the Zero Product Property to find the x-intercepts:

0=2x-5\\5=2x\\x=\frac{5}{2}

0=x+1\\x=-1

Hence, the x-intercepts for the graph of f(x) are x=-1 and x=\frac{5}{2}.

<u>Part B</u>

Find the x-coordinate of the vertex:

x=-\frac{b}{2a}\\ \\x=-\frac{(-3)}{2(2)}\\\\x=\frac{3}{4}

Find the y-coordinate of the vertex:

f(\frac{3}{4})=2(\frac{3}{4})^2-3(\frac{3}{4})-5=-\frac{49}{8}

Hence, the vertex is (\frac{3}{4},-\frac{49}{8}). We can see from the positive leading coefficient of the function that the vertex will be a minimum because the parabola will open faced-up.

<u>Part C</u>

You can use the x-intercepts and vertex to plot points of the graph of the function. Additionally, you can throw in the y-intercept in as well. The y-intercept, in this case, is f(0)=2(0)^2-3(0)-5=-5, or (0,-5) as an ordered pair. See attached graph.

8 0
2 years ago
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