Question

A quadratic function f(x)=ax2 passes through (0,0) and (5,5). write an equation for this function

Answer 1

Answer:

y = (1/5)x² or  y = x²/5

Step-by-step explanation:

We have the function f(x) = ax² and are given that the point (5,5) is on the parabola.  We need to find 'a'.   f(x) can be replaced with 'y', so we can rewrite the equation as...

y = ax²    

We know that when x = 5, y = 5, so we have

5 = a(5²)      now simplify...

5 = 25a

5/25 = a

1/5 = a, so our equation becomes

(1/5)x² or  x²/5  (the expressions are equal)