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laila [671]
3 years ago
14

A quadratic function f(x)=ax2 passes through (0,0) and (5,5). write an equation for this function

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

y = (1/5)x² or  y = x²/5

Step-by-step explanation:

We have the function f(x) = ax² and are given that the point (5,5) is on the parabola.  We need to find 'a'.   f(x) can be replaced with 'y', so we can rewrite the equation as...

y = ax²    

We know that when x = 5, y = 5, so we have

5 = a(5²)      now simplify...

5 = 25a

5/25 = a

1/5 = a, so our equation becomes

(1/5)x² or  x²/5  (the expressions are equal)

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Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co
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(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

Step-by-step explanation:

Given

Minimum\ Area = 135cm^2

Maximum\ Area = 155cm^2

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Required

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To do this, we simply calculate the areas of all the given circles

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<em></em>

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