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3 years ago

Can someone help me with this question please.

Mathematics

1 answer:

drek231 [11]3 years ago

3 0

Answer:

a). 3a² + 17a - 1

b). 4y (7y-6)

Step-by-step explanation:

in the second question, we find a number that can divide 28 and 24 without a remainder, which is 4

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What is the measure of angle A? A. 110 B. 70 C. 250 D. 55

zhuklara [117]

B. 70 is the correct answer

8 0

3 years ago

Read 2 more answers

Please I need help asap

jasenka [17]

Answer:

Option D - x = 3 3/5

Step-by-step explanation:

Lets make the left side into an improper fraction :

2 2/5 = 12/5

Now let's make both fraction into equivalent ones but with the same denominator :

2/3 = 10/15

12/5 = 36/15

Now we substitute the equivalent values back into the equation :

10/15 × x = 36/15

Now we multiply both sides by 15 to remove the denominators:

10 × x = 36

Now we divide both sides by 10 and simplify :

x = 36/10

x = 18/5

x = 3 3/5

So our answer will be Option D

Hope this helped and brainliest please

7 0

2 years ago

A study of 40 English composition professors showed that they spent, on average, 13 minutes correcting a student's term paper. T

photoshop1234 [79]

Answer:

90% confidence interval for the mean grading time of all composition papers.

(12.47981 , 13.52019)

Appropriate inequality

The interval is ( 12.47981 < μ < 13.52019)

Step-by-step explanation:

Explanation:-

Given sample size 'n' = 40

Mean of the sample = 13 minutes

standard deviation = 2 min

level of significance = 0.10 or 90%

90% confidence interval for the mean grading time of all composition papers.

$( x^{-} - Z_{0.1} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.10} \frac{S.D}{\sqrt{n} } )$

$( 13 - 1.645 \frac{2}{\sqrt{40} } , 13 +1.645 \frac{2}{\sqrt{40} } )$

( 13 - 0.52019 , 13 + 0.52019)

(12.47981 , 13.52019)

The interval is ( 12.47981 < μ < 13.52019)

7 0

3 years ago

Select the correct answer from the drop-down menu.

ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$ .

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

$=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

$=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

$=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$ .

Given the quotient of $-8x^2y^3 \div xy$ is same as the product of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0

3 years ago

Ining How to Verify an Answer

Talja [164]

No she did the Division wrong because she got 5 1/2 for her multiplication it so she should recheck and try the multiplication over to get the answer right

4 0

3 years ago