x is less than or equal to -4 or x is greater than or equal to 5
x <= -4 or x>= 5
There is no intersection of both inequalities when we graph it in number line So, we write the interval notation separately for each inequality
for x<=-4 , x starts at -4 and goes to -infinity because we have less than symbol. Also we have = sign so we use square brackets
Interval notation is (-∞ , -4]
for x>= 5 , x starts at 5 and goes to infinity because we have greater than symbol. Also we have = sign so we use square bracket at 5
Interval notation is [5 , ∞)
Now combine both notation by a 'U' symbol Union
(-∞ , -4] U [5 , ∞)
This is an excellent practice for the solution of quadratic equations.
1*36=36 => (1,36)
2*18=36 => (2,18)
3*12=36 => (3,12)
4*9=36 => (4,9)
6*6=36 => (6,6)
9*4=36 => (9,4)
12*3=36 => (12,3)
18*2=36 => (18,2)
36*1=36 => (36,1)
We can see that the sum decreases until the two factors are close (or equal) and then increases again.
The pair of integers with a sum of 20 is therefore (2,18) or (18,2).
Answer:
The solution region is x < –5 and x > 2
Step-by-step explanation:
We are given the inequalities, 2x–2 < –12 or 2x+3 > 7
Upon simplifying the inequalities, we get,
A. 
i.e. 
i.e. 
B. 
i.e. 
i.e. 
So, we get the solution is 
or 
and the plotted region can be seen below.
Answer:
80%
Step-by-step explanation:
I'm assuming you want the average of the class.
62 + 78 + 83 + 84 + 93
= 400
400/5
= 80
Therefore Victor's overall test score is 80%
Slope formula is the answer
