(x^2+5x-36)/(x^2-16)
=(x^2+9x-4x-36)/(x^2-4^2)
=x(x+9)-4(x+9)/(x+4)(x-4)
=(x-4)(x+9)/(x+4)(x-4)
=x+9/x+4
Hope this helps.
Given:
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary
Complementary angles have a sum of 90°
Angle A = x + 4° ; Angle B = x
x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.
Angle A = x + 4° ⇒ 43° + 4 = 47°
Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°
Angle D = 5x ; Angle E = x
5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30° Angle E.
Angle D = 5x = 5(30) = 150°
Answer:
40m Since it is the shortest side
Step-by-step explanation:
Answer:solo quiero puntos :(
Step-by-step explanation:
Answer:
324 teachers
Step-by-step explanation:
3 teachers of every 50 students
__ teachers of 5400 students
so,
therefore,
