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4 years ago

Consider the polynomial 16x2 - 1 what is the value of ac what is the value of b

Mathematics

2 answers:

ddd [48]4 years ago

6 0

Answer:

ac= -16

b=0

$(4x+1)(4x-1)$

Step-by-step explanation:

$16x^2 -1$

WE write the given polynomial in standard form ax^2 + bx+c

there is no x term so we include 0x

the given expression becomes

$16x^2+0x-1$

The value of a= 16 , b= 0 and c=-1

$ac= a*c = 16 * (-1) = -16$

The value of b = 0

Two number to multiply to get ac = -16 are 4 and -4

When we add two numbers we will get

-4 + 4= 0

using factors -4 and 4 , the expression becomes

$16x^2-4x+4x-1$

$(16x^2-4x)+(4x-1)$

Factor out GCF

$4x(4x-1)+1(4x-1)$

$(4x+1)(4x-1)$ is the factored form

Sergeu [11.5K]4 years ago

4 0

the answer is

-16

-4and4

(4x-1)(4x+1)

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