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klemol [59]
3 years ago
10

What is 4 divide by 2

Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Answer:

2

Step-by-step explanation:

hope this helped

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John works two jobs. As a security guard he earns $8.50 per hour. As a landscaper he earns $14 per hour. One week John worked a
Rashid [163]

Answer:

John work as a security guard job <u>27 hours</u> and as a landscaper <u>33 hours</u>.

Step-by-step explanation:

Given:

John works two jobs.

As a security guard he earns $8.50 per hour and as a landscaper he earns $14 per hour.

One week John worked a total of 60 hours and earned $691.50.

Now, to find hours he work at each job.

Let the job of security guard be x hours.

And the job of landscaper be y hours.

So, the total hours John worked in a week:

x+y=60.

⇒ y=60-x.............( 1 )

<em>Now, the money earned by John in a week:</em>

8.50x+14y=691.50

<em>Putting the equation ( 1 ) in the place of y:</em>

⇒ 8.50x+14(60-x)=691.50

⇒ 8.50x+840-14x=691.50

<em>Moving variables on one side and the other we get:</em>

⇒ 840-691.50=14 x-8.50x

⇒148.50=5.50x

<em>Dividing both sides by 5.50 we get:</em>

⇒ 27=x

<u>As a security guard job he worked 27 hours</u><u>.</u>

Putting the value of in x equation ( 1 ) we get:

y=60-27

⇒ y=33.

<u>As a landscaper he worked 33 hours</u>.

Therefore, John work as a security guard job 27 hours and as a landscaper 33 hours.

5 0
3 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
The equation y = 36 + 18x models the relationship
wariber [46]

Answer:

Option B) The height, in inches, of a typical apple tree

Step-by-step explanation:

Let

x----> the number of years, after the tree was planted

y ---> the height in inches, of a typical golden  delicious apple tree

we have

y=36+18x

Remember that

The y-intercept is the value of y when the value of x is equal to zero

In this problem

The y-intercept is the height of the tree when it was planted (x=0)

8 0
3 years ago
Carly can ride her bicycle 6000 meters in 15 minutes how far can she ride her bicycle in two minutes
Gala2k [10]
C. 800 Meters hope I helped

5 0
3 years ago
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