Answer:
5
Step-by-step explanation:
<u>P</u>arenthesis
<u>E</u>xponents
<u>M</u>ultiplication
<u>D</u>ivision
<u>A</u>ddition
<u>S</u>ubtraction
<em><u>Following the order, first is parenthesis:</u></em>
3 · 5 - 2(5)
<em><u>Multiplication:</u></em>
15 - 10
5
The answer would be Without changing the compass width, draw an arc from point N which intersects the
segment NT at a point X.
Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
Answer: x = 4
Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.
Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.
Then (13 ft)^2 = (5 ft)^2 + y^2, or
169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.
Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."
Answer:
x<_-2 ( x is less than or equal to -2)
Step-by-step explanation:
First remove opposites and collect like terms so it will be -4x+12+4x<_-8x-8x-20.
Then move them to be 12<_-16x-20.
Move -16x to the left and the 12 to the right to combine it with -20 to become -32.
You are now left with 16x<_-32.
Divide both sides by 16 to get x<_-2.
Hope this helped :) btw <_ is less than or equal to i just dont know how to put the sign on top of the underscore :/
