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3 years ago

How do I solve this equation -9x+1=80

2 answers:

6 0

-9x + 1 = 80....subtract 1 from both sides
-9x + 1 - 1 = 80 - 1...simplify
-9x = 79...divide both sides by -9
x = -79/9 <== ur answer

Ber [7]3 years ago

3 0

-9x+1=80
Subtract 1 both sides.
-9x=79
Then divided by -9
The answer is -8.77 or -8.8

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Answer:

<em>Choose the first alternative</em>

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Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

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