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tankabanditka [31]

2 years ago

15

I need to understand the solution

1 answer:

alina1380 [7]2 years ago

5 0

Answer:

17:3

Step-by-step explanation:

Hope this helps!

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On Monday morning the temperature was 38°F, but by the afternoon the temperature had risen 22°F. On Tuesday morning the temperat

Anika [276]

The temperature on Tuesday afternoon is below 38 degrees Fahrenheit. As it states in the question the temperature on Tuesday morning was 27 degrees Fahrenheit and rose 10 more degrees at noon. Which makes is 37 degrees Fahrenheit at noon on Tuesday. You get this by taking 27 degrees and adding 10 degrees.

7 0

2 years ago

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Twenty less than a number is more than twice the same number . Step by step to get the answer

likoan [24]

20 less than (-20) a number (n) is more than (>) twice the same number (2n)
-20+n>2n
minus n both sides
-20>n
n<-20

3 0

3 years ago

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33. Suppose you were on a planet where the

tatyana61 [14]

<u>Answer:</u>

a) 3.675 m

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

A fair dice is rolled 3 times in a row. The outcomes are shown below. Calculate the probability of all three events occurring. R

velikii [3]

Answer:

5/54

Step-by-step explanation:

probability of the dice being 5 = 1/6

probability of the dice being a factor of 6 = 4/6

probability of the dice being more than 1 = 5/6

1/6 * 4/6 = 4/36

4/36 * 5/6 = 20/216

20/216 simplified to lowest is equal to 5/54

5 0

2 years ago

Given m||n , find the value of . (x+27)^ (2x-7)^

KATRIN_1 [288]

Answer:

We love a good sister who’s stressed

Step-by-step explanation:

From jamsie pooh

8 0

2 years ago