Answer:
C. 125 + 120x = 180 + 110x
t = $5.5
Step-by-step explanation:
A.125t + 120 = 180t + 110
B. 120t + 110t = 125 + 180
C. 125 + 120t = 180 + 110t
D. 125 - 120t = 180 - 110t
Friday
$125 + 120t
Saturday
110t + 180
equate Friday and Saturday
125 + 120t = 110t + 180
Collect like terms
125 - 180 = 110t - 120t
-55 = -10t
Divide both sides by -10
t = -55 / -10
= 5.5
t = $5.5
Answer:
Option A.
Step-by-step explanation:
We need to find a table for which the y-value will be the greatest for very large values of x.
From the given table it is clear that the largest value of x in all tables is 5.
In table A, y=64 at x=5.
In table B, y=32 at x=5.
In table C, y=40 at x=5.
In table D, y=13 at x=5.
It is clear that 64 is the greatest value among 64, 32, 40 and 13.
It means table in option A represents the function for which the y-value will be the greatest for very large values of x.
Therefore, the correct option is A.
Answer:
75,000,012
Step-by-step explanation:
enjoy, i guess
Answer:
Problem 9: -1/2
Problem 10: 1/5
Step-by-step explanation:
Problem 10: Label the given ln e^(1/5) as y = ln e^(1/5).
Write the identity e = e. Raise the first e to the power y and the second e to the power 1/5 (note that ln e^(1/5) = 1/5). Thus, we have:
e^y = e^(1/5), so that y = 1/5 (answer).
Problem 9: Let y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) 1 /2
Write out the obvious:
4 = 4
Raise the first 4 to the power y and raise the second 4 to the power (log to the base 4 of) 1 /2. This results in:
4^y = 1/2. Solve this for y.
Note that 4^(1/2) = 2, so that 4^(-1/2) = 1/2
Thus, y = -1/2
