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3 years ago

if A is the midpoint of line segment PR, PA= 7x-11, and PR= 8x+14, then what is the value of line segment AR?

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

PA+AR=PR

AR= PR- PA

AR= 8x+14-(7x-11)

AR= 8x+14-7x+11

AR= x+25

Now, if A is midpoint of PR, then

PA=AR

7x-11= x+25

6x=36

x=6

Put value of x in AR

AR= 6+25= 31

Hope this will help:)

torisob [31]3 years ago

6 0

Answer: x+25

Step-by-step explanation:

Here.

PR = 8x+14

& PA = 7x-11

and A is the mid point of PR

so according to condition , PR - PA = AR

⇒ 8x + 14 -(7x -11) =AR

⇒8x +14 -7x + 11 = AR

∴ AR = x+25

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