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alexandr402 [8]
3 years ago
10

Solve the system of equations using elimination. 2x – 3y = 9 and 3x + 2y = –6

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0
We will multiply the given equations so that the x component is cancels out upon addition...

-3(2x-3y=9)+2(3x+2y=-6)  perform indicated operations.

(-6x+9y=-27)+(6x+4y=-12)  which is equal to:

13y=-39  divide both sides by 13

y=-3, making <span>2x-3y=9 become:

2x-3(-3)=9

2x+9=9  subtract 9 from both sides

2x=0  divide both sides by 2

x=0

So the solution to the system is the point (0,-3)...

You can check with the two original equations...

2(0)-3(-3)=9, 9=9

3(0)+2(-3)=-6, -6=-6</span>
Whitepunk [10]3 years ago
5 0
(0,-3) is the point which is your system of equations using elimination answer
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