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alexandr402 [8]
3 years ago
10

Solve the system of equations using elimination. 2x – 3y = 9 and 3x + 2y = –6

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0
We will multiply the given equations so that the x component is cancels out upon addition...

-3(2x-3y=9)+2(3x+2y=-6)  perform indicated operations.

(-6x+9y=-27)+(6x+4y=-12)  which is equal to:

13y=-39  divide both sides by 13

y=-3, making <span>2x-3y=9 become:

2x-3(-3)=9

2x+9=9  subtract 9 from both sides

2x=0  divide both sides by 2

x=0

So the solution to the system is the point (0,-3)...

You can check with the two original equations...

2(0)-3(-3)=9, 9=9

3(0)+2(-3)=-6, -6=-6</span>
Whitepunk [10]3 years ago
5 0
(0,-3) is the point which is your system of equations using elimination answer
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Answer:

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Step-by-step explanation:

This is  the method I am familiar with.

I Hope It helps :)

METHOD- 1 : Elimination\\6x - 2y=10------(1)\\2x+3y =51------(2)\\Multiply -eq-(1)- by -the-coefficient-of-x-in-equation (2)\\Multiply-eq-(2) -by -the-coefficient-of-x-in-equation (1)\\6x - 2y=10------(1) *2\\2x+3y =51------(2)*6\\\\12x-4y=20 ------(3)\\12x+18y=306 ------(4)\\Subtract -eq- (4)- from- eq -(3)\\-22y =-286\\\frac{-22y}{-22} =\frac{-286}{-22} \\y =13\\

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3 years ago
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