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3 years ago

Please Help me ASAP VERY URGENT

Mathematics

2 answers:

jenyasd209 [6]3 years ago

6 0

Answer:

A= 115 degrees

C= 50 degrees

Step-by-step explanation:

All angles are equal to 180 so the equation is:

180=4x-13+x+18+15

180=5x+20

160=5x

x=32

saw5 [17]3 years ago

5 0

Answer: x = 32 because 4 times 32 = 128 and 128 - 13 = 115 and 115 + 15 = 130 and 32 + 18 = 50 and 130 + 50 = 180. the angle for A is 115 and the angle for C is 50. Hope it Helps.

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The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in

Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

because the distance from the x-axis to the point is 4 (y-coordinate)

and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

* Lets solve the problem

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

8 0

3 years ago

PLS HELP ILL MARK BRAINLIST!!

hammer [34]

Answer:

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3 years ago

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Segment BD is an altitude of triangle ABC. Find the area of the triangle.

Sever21 [200]

Answer: The correct option is A, i.e., 7.5.

Explanation:

It is given that ABC is a triangle and BD is an altitude.

Since BD is an altitude, therefore the height of the triangle is BD and the base of the triangle is AC.

The distance formula to find the distance between two points is,

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

First, we find BD, where B(-1,4) and D(2,4).

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So, the height of the triangle is 3.

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$AC=\sqrt{(6-1)^2+(2-2)^2}=\sqrt{25} =5$

So, the base of the triangle is 5.

The formula to find the area of a triangle is,

$A=\frac{1}{2}\times {\text{base}}\times {\text{height}}$

$A=\frac{1}{2}\times 5\times 3=\frac{15}{2}=7.5$

Therefore, the area of the triangle is 7.5 unit square and the correct option is A.

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3 years ago

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lukranit [14]

Answer:

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2 years ago

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