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likoan [24]
3 years ago
11

21. Which is the correct answer

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Jajajjajajjaajajajajajja

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Sever21 [200]

Answer: Don't know sorry

Step-by-step explanation:

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Show your work<br> Number 19 only
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Maybe

Step-by-step explanation:

Assuming that the diamater is 16 inches, then yes because the pizza is twice as big, it should be twice as much.

But because it is not stated in the question that it is 16 inches in <u><em>diamater,</em></u> I will not say yes. It could be 16 inches in radius, curcumfrience, or area.

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Whoever gives me points and thanks gets them back :O
Misha Larkins [42]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°
Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1

If 36 adults are randomly​ selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.4 - 98.6}{0.1}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0
3 years ago
A jeweler has 5 rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. she decides to melt down the rings and a
ankoles [38]
Silver = 10%
Gold = 90%

Amount of gold to be deducted
90/100 × 18 = 16.2 g

75/100 × 18 = 13.5

16.2 - 13.5 = 2.7

Amount o silver to added.
  2.7 × 5 = 13.5


Answer = 13.5 g

7 0
3 years ago
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