Question

LM has endpoints L(-1 1) and M(-5 -3) find the coordinates of the midpoint of LM

Answer 1

$\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) L&({{ -1}}\quad ,&{{ 1}})\quad % (c,d) M&({{ -5}}\quad ,&{{ -3}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ LM=\left(\cfrac{{{ -5}} -1}{2}\quad ,\quad \cfrac{-3+1}{2} \right)$

Answer 2

Answer:

Midpoint of LM is (-3-1).

Step-by-step explanation:

LM has endpoints L(-11) and M(-5-3)

We have to find the coordinates of mid point of LM

If a line segment has two end points (x,y) and (x',y') then x-coordinates of the midpoint will be

x = $\frac{x+x'}{2}$

and y coordinates will be

Y =  $\frac{y+y'}{2}$

Now we put the values of endpoints to find midpoint of LM.

X =  $\frac{-5-1}{2}$ =  $\frac{-6}{2}$ = -3

Y =  $\frac{1-3}{2}$ =  $\frac{-2}{2}$ = -1

Therefore, mid point of LM is (-3-1).