In this specific case, the <em>initial term</em> (a) is 5 and the <em>common ratio</em> (r) is -2
Henceforth, after determining what a and r are, we use the formula for the <em>nth term</em>. Which is:

Therefore, the 14th term is :

Hope it helps!
The end behaviour of the polynomial graph is (b) x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝
<h3>How to determine the end behaviour of the polynomial graph?</h3>
The polynomial graph represents the given parameter
This polynomial graph is a quadratic function opened downwards
Polynomial function of this form have the following end behaviour:
- As x increases, f(x) decreases
- As x decreases, f(x) decreases
This is represented as
x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝
Hence, the end behaviour is (b)
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Line of best fit also known as a linear regression or a trend line, the line of best fit is common tool for showing how two variables are related.This can be established by:
Positive correlation
all scatter plots
negative correlation
Line of best fit is used in order to demonstrate any observed trends in order to predict future outcomes regarding the data point variable in use.
Complementary means they add to 90°
f=90-g
f=4g
4g =90-g
5g=90
g=18
f=4g=4(18)=72
Answer: f=72°, g=18°
<u>Hint </u><u>:</u><u>-</u>
- Break the given sequence into two parts .
- Notice the terms at gap of one term beginning from the first term .They are like
. Next term is obtained by multiplying half to the previous term . - Notice the terms beginning from 2nd term ,
. Next term is obtained by adding 3 to the previous term .
<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>
We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,
.
We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,
Notice the term
will be too small , so we can neglect it and take its approximation as 0 .

Now the second sequence is in Arithmetic Progression , with common difference = 3 .
![\implies S_2=\dfrac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%20)
Substitute ,
![\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7B25%7D%7B2%7D%5B2%284%29%20%2B%20%2825-1%293%5D%20%3D%5Cboxed%7B%20908%7D%20)
Hence sum = 908 + 1 = 909