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lesya692 [45]
2 years ago
6

What is the value of x? 4 8 6 10

Mathematics
1 answer:
dsp732 years ago
8 0

Answer:

The right answer for the question is 6.

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Explain the steps to finding the vertex of g(x) = 3x2 + 12x + 15
RUDIKE [14]

Answer:

The vertex of this parabola, (-2, 3), can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

g(x) = a\, (x - h)^2 + k,

where a, h, and k are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at (h,\, k).

The vertex form can be expanded to obtain:

\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}.

Compare that expression with the given equation of this parabola. The constant term, the coefficient for x, and the coefficient for x^2 should all match accordingly. That is:

\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right..

The first equation implies that a is equal to 3. Hence, replace the "a\!" in the second equation with 3\! to eliminate \! a:

(-2\times 3)\, h = 12.

h = -2.

Similarly, replace the "a" and the "h" in the third equation with 3 and (-2), respectively:

3 \times (-2)^2 + k = 15.

k = 3.

Therefore, g(x) = 3\, x^2 + 12\, x + 15 would be equivalent to g(x) = 3\, (x - (-2))^2 + 3. The vertex of this parabola would thus be:

\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}.

8 0
3 years ago
What is the area of circle with a radius of 13 milimeters? use 3.14 for pi
MrRissso [65]

Answer:

530.66 mm²

5.3066 cm²

Step-by-step explanation:

A = π·r²

= 3.14×(13mm)²

= 3.14×169mm²

= 530.66 mm²

= 5.3066 cm²

8 0
3 years ago
Read 2 more answers
Determine whether the following function is one-to-one. f ( x ) = 6 x + 1
seraphim [82]

Answer:

one to one function

Step-by-step explanation:

f(x)=6x+1 can only be a one to one function when x1=x2

Now,

f(x1)=f(x2)

or, 6x1 + 1 = 6x2 + 1

or, 6x1 = 6x2

or, x1 = x2

So f(x)= 6x + 1 is a one to one function

4 0
2 years ago
$11.13-$5.50-$6.12=$10.51; $30- $10.51
MrMuchimi
What is the problem?? I would love to help
3 0
3 years ago
Can someone help me please
zubka84 [21]
It’s too small zoom in some I will be glad to assist you
7 0
3 years ago
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