Answer:
49N
Step-by-step explanation:
Step one
Given
When the force of 63 N acts on a certain object
the acceleration of the object is 9/ms^2
Firstly, we need to calculate the mass m
F=ma-------1
m= F/a
m= 63/9
m= 7kg
Step two:
Also, if the acceleration of the object becomes 7 m/s^2
then the force
Note: the mass remains the same= 7kg
F=ma
F=7*7
F= 49N
U times any number by 3 and see witch ones the closest
27x3=81 that's what I think and that's the closest
A common ratio for that sequence is r = 5/1
1. expand using place value.
337,060 = 300,000 + 30,000 + 7,000 + 000 + 60 + 0
Next, we will use exponents:
300,000 = 3 * 10^5
30,000 = 3 * 10^4
7,000 = 7 * 10^3
000 = 0 * 10^2
60 = 6 * 10
0 = 0 * 10^0
then after combing these exponents, we can write the number as:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 0 * 10^2 + 6 * 10 + 0 * 10^0
Finally, removing the meaningless zeroes, we would end up with:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 6 * 10
Answer:
x=5
Step-by-step explanation:
We can write ratios to help us solve
4x 12 +3
---------- = ------------
3x+1 12
Using cross products
4x*12 = (3x+1) * (15)
48x = 45x +15
Subtract 45x from each side
3x =15
Divide by 3
3x/3 =15/3
x=5
