The answer is false. To explain further, let G have vertices
{v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on
the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass
of as a minimum of 5, so the tree containing of a track through vertices v3, v2,
v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently
its total mass is greater than that of the tree with edges from v1 to every
single vertex.
The answer is D glycolysis
Answer:
B? Hope this helps, sorry if it's wrong.
Explanation:
The other two Domains being "Bacteria" and "Eukarya" (which includes us humans). Archaebacteria<span> are characterized by having different cell call components, coenzymes and RNA Sequences compared to bacteria. ... </span>Eubacteria<span> have a rigid cell wall. However, they can be both gram positive and gram-negative.</span>
The statements 1-4 are true