We can start this problem by finding out what the lowest consecutive number's value is (x). Since consecutive numbers are numbers that are 1 apart from each other, the sum of 9 consecutive numbers would look like
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8)
Since we know that they equal 153,
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 153
Now we combine like terms
9x + 36 = 153
Simplify
9x = 117
x = 13
Now, we need to find what the 5th consecutive number is equal to. The fifth consecutive number is (x+4), so 13 + 4 is 17, meaning that the 5th of 9 consecutive numbers that add up to 153 is 17.
We can solve this equation by completing the square. Notice that

and

. Therefore, we can turn

into

. y, in this equation, only has one real solution: 4. So your answer would be (B).
Answer:
If Discriminant,
Then it has Two Real Solutions.
Step-by-step explanation:
To Find:
If discriminant (b^2 -4ac>0) how many real solutions
Solution:
Consider a Quadratic Equation in General Form as

then,
is called as Discriminant.
So,
If Discriminant,
Then it has Two Real Solutions.
If Discriminant,
Then it has Two Imaginary Solutions.
If Discriminant,
Then it has Two Equal and Real Solutions.
Answer:
504 in3
Step-by-step explanation:
I did the I-Ready too.