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3 years ago

The mass of the moon is 7.36*10^25 grams to the nearest tenth how many moons would it take to equal the mass of earth

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

Nearly 81 moons will be required to equate the mass of moon to the mass of earth.

Step-by-step explanation:

Mass of earth is 5.972*10^24 kg.

Mass of the moon is 7.36*10^25 g = 7.36*10^22 kg

As mass of the Earth is given as 5.972 * 10^24 kg and mass of the moon is given as 7.36 * 10^22 kg, then the number of moons required to make it equal to the mass of earth can be calculated by taking the ratio of mass of earth to moon.

Mass of Earth = Number of moons * Mass of Moon

Number of Moons = Mass of Earth/Mass of moon

Number of moons = 5.972 * 10^24/7.36*10^22= 81 moons.

So nearly 81 moons will be required to equate the mass of moon to the mass of earth.

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Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago

1. Suppose that F(x) varies directly with x and f(x) = 160 when x = 5.

weeeeeb [17]

The answer to question number 1 is 16.

6 0

3 years ago

Read 2 more answers

What is the answer to this... plz answer only if you are correct!

Ilia_Sergeevich [38]

Answer: 39

Step-by-step explanation:

subtrack 61 and 22

7 0

2 years ago

Read 2 more answers

Can i have some help with this?

irina [24]

Answer:

10.75 cm^2

Step-by-step explanation:

1. Area of semicircle, A= (pi x R^2) divided by 2

2. A= (3.14 x 5^2) divided by 2 = 39.25

3. Area of rectangle, A= l x w

4 A= 10 x 5 = 50

5. subtract

6. 50 - 39.25

7. 10.75

6 0

3 years ago

Help me and i’ll mark you brainliest plus you get 20 points !!!!

Anton [14]

Answer:

Angle bisector

Step-by-step explanation:

Find the measure of the angle COA. By angle addition postulate,

$m\angle COX=m\angle AOX+m\angle COA$

From the diagram,

$m\angle COX=80^{\circ}\\ \\m\angle AOX=40^{\circ},$

then

$80^{\circ}=m\angle COA+40^{\circ}\\ \\m\angle COA=80^{\circ}-40^{\circ}=40^{\circ}$

Find the measure of the angle BOA. By angle addition postulate,

$m\angle BOX=m\angle AOX+m\angle BOA$

From the diagram,

$m\angle BOX=60^{\circ}\\ \\m\angle AOX=40^{\circ},$

then

$60^{\circ}=m\angle BOA+40^{\circ}\\ \\m\angle BOA=60^{\circ}-40^{\circ}=20^{\circ}$

Find the measure of the angle COB. By angle addition postulate,

$m\angle COX=m\angle BOX+m\angle COB$

From the diagram,

$m\angle BOX=60^{\circ}\\ \\m\angle COX=80^{\circ},$

then

$80^{\circ}=m\angle COB+60^{\circ}\\ \\m\angle COB=80^{\circ}-60^{\circ}=20^{\circ}$

This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA

6 0

3 years ago