Help me with this one someone please

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

3 years ago

How do you do #5 a b c

Brut [27]

B i think the answer is for #5

4 0

3 years ago

Find the common difference of the arithmetic sequence 5, 14, 23, ...

vodka [1.7K]

It’s plus 9 so the next number should be 32

7 0

3 years ago

Read 2 more answers

Use technology or a z-score table to answer the question.

FinnZ [79.3K]

Answer:

C

Step-by-step explanation:

First we find the z-score.

z = (x - μ) / σ

z = (520 - 500) / 60

z = 0.33

Using a calculator or z-score table:

P(z < 0.33) = 0.6293

The probability is approximately 63%. Answer C

6 0

3 years ago

Can someone plz help me no links plz I beg u I’m confused I would really appreciate it

Ghella [55]

Answer: A

Step-by-step explanation:

The maximum amount of weight the truck can carry is 1600lbs. You do not want to exceed 1600lbs, but you can reach 1600lbs. This makes the inequality symbol ≤. This symbol says that the weight load has to be less than 1600lbs, but It can equal 1600lbs. You know that the piano is 400lbs and each box is 50lbs. Since you want to figure out how many boxes you can put on the truck alongside the piano, you can use the inequality: 50x + 400 ≤ 1600.

50 represents pounds per/box

x represents the number of boxes you can hold

400 represents the weight of the piano

1600 represents the max weight.

8 0

2 years ago