PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
- 2 1/4 (mix fraction)
- 9/4 (improper fraction)
Answer:
13 units
given two points: (−3, −8) and (10, −8)
As the y coordinates are same.
use the method:
|x2| + |x1| where (x1, y1), (x2, y2)
Solve:
|10| + |-3|
10 + 3
13
Answer:
228 hydrogen atoms
Step-by-step explanation:
In a water molecule,
1/3rd is oxygen atoms, and
2/3rd (1 - 1/3 = 2/3) is hydrogen atoms
If there are 114 water molecules,
Total number of atoms would be:
3 * 114 = 342 (1 oxygen and 2 hydrogen atoms in 1 water molecule)
Out of these, 2/3rd would be hydrogen atoms, so:
There would be 228 hydrogen atoms
Answer:
7 bags per hour
Step-by-step explanation:
To determine how many bags she sells per hour
Take the total number of bags and divide by the number of hours
35 bags/ 5 hours
7 bags per hour
