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3 years ago

Which of the following is E ∪ F?

1 answer:

5 0

For E the answer is 2. Because the square of 1 is one and 9 is three. And 2 to the square root of two which would be 2 time 2= 4

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Find the area of the figure below. Round to the nearest tenth.

leva [86]

6x9 + 3^2pi would be the area so 54+9pi=57.14

4 0

3 years ago

In a class there are 15 boys and 15 girls 5/6 of the children have brown hair if someone is chosen at random what is the probabi

Cloud [144]

Probability someone chosen at random will not have brown hair = 1/6

<h3>Probability of two variables</h3>

The number of girls = 15

The number of boys = 15

The total number of children = 15 + 15 = 30

Probability that someone chosen at random will have a brown hair, P(Brown hair) = 5/6

P(Brown hair) + P(Not Brown hair) = 1

5/6 + P(Not brown hair) = 1

P(not brown hair) = 1 - 5/6

P(not brown hair) = 1/6

Therefore, if someone is chosen at random, probability that they will not have brown hair = 1/6

Learn more on probability here: brainly.com/question/27899440

#SPJ1

6 0

2 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

5 0

3 years ago

How many minutes of calling time do the plans cost the same amount ?

Mama L [17]

D 200 minutes

.15*200 = 30+45= Plan A= $75
.25*200= 50+25= Plan B= $75

Answer is D

7 0

3 years ago

One grain of this sand approximately weighs 6 x 10^-6g.

emmasim [6.3K]

Answer:

1.2×10¹² grains

Step-by-step explanation:

1 grain = 6×10⁻⁶ g

7200 kg =
7200000 g =
7.2×10⁶ g =
7.2×10⁶ ÷ 6×10⁻⁶ =
(7.2÷6)×10⁶⁻ ⁽⁻⁶⁾ =
1.2×10¹² grains

4 0

3 years ago