Answer:
x=2
Step-by-step explanation:
let x be the edge length of the square removed at each corner;
Hence the area of the base is:
Using the quadratic equation formula, or completing the square, x, or length of a side of one of the squares is x=2 or x=58
#Given that x=58 is larger than 40cm, the side length is x=2
Given:
x and y are both differentiable functions of t.
To find:
The value of .
Solution:
We have,
...(i)
At x=-1,
Divide both sides by 3.
Taking cube root on both sides.
So, y=2 at x=-1.
Differentiate (i) with respect to t.
Putting x=-1, y=2 and , we get
Divide both sides by -8.
Therefore, the value of is 36.