Answer:
5 people will be left to play
Answer:
x = -2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
8x + 4(x - 3) = 4(6x + ) -4
8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)
8x + 4x + -12 = 24x + 16 + -4
(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)
12x + -12 = 24x + 12
12x -12 = 24x + 12
Step 2: Subtract 24x from both sides.
12x -12 -24x = 24x + 12 -24x
-12x -12 = 12
Step 3: Add 12 to both sides.
-12x - 12 + 12 = 12 + 12
-12x = 24
Step 4: Divide both sides by -12.
-12x/-12 = 24/-12 <u>x = -2</u>
HOPE THIS HELPED!!!
Answer:
A
Step-by-step explanation:
A parcent as a fraction would be /100. So the answer would not be C or D. And since it isn't B, the answer is only A
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Answer:convergent
Step-by-step explanation:
Given
Improper Integral I is given as


integration of
is 
![I=1000\times \left [ e^x\right ]^{0}_{-\infty}](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5Ex%5Cright%20%5D%5E%7B0%7D_%7B-%5Cinfty%7D)
![I=1000\times I=\left [ e^0-e^{-\infty}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20I%3D%5Cleft%20%5B%20e%5E0-e%5E%7B-%5Cinfty%7D%5Cright%20%5D)
![I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5E0-%5Cfrac%7B1%7D%7Be%5E%7B%5Cinfty%7D%7D%5Cright%20%5D)

so the integration converges to 1000 units