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Fittoniya [83]
3 years ago
10

2 2/4 devided by 1/6

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0
(15 is your answer)

Divide numerator by denominator, cancel out any common factors
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5 0
3 years ago
True or False? When Samantha includes more batteries in her project, the current in her project increases. Current is the indepe
Semmy [17]
True....Independent = Test....therefore they are testing the current
7 0
3 years ago
Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then
Debora [2.8K]
To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form f(x)=x^2+bx+c it vertex (h,k) is given by h= \frac{-b}{2a}, k=f(h).
We can infet from our parabola that a=2 and b=-12. So lets replace those values in our formula:
h= \frac{-b}{2a}
h= \frac{-(-12)}{2(2)}
h= \frac{12}{4}
h=3
k=f(h)=2(3)^2-12(3)+19
k=2(9)-36+19
k=18-17
k=1
The vertex (h,k) of our parabola is (3,1)

Now to find our second point, we are going to evaluate our parabola at x=0
f(0)=2(0)^2-12(0)+19
f(0)=0+0+19
f(0)=19
Our second point is (0,19)

We can conclude that we can graph the parabola f(x)=2x^2-12x+19 using its vertex (3,1) and the point (0,19) as follows: 

7 0
3 years ago
Suppose you are putting up a tent for a camping trip.
SSSSS [86.1K]

The length of the rope needed is 15 feet

Given the following parameters;

  • Height of the pole = 9 foot
  • The distance from the <u>rope away from the base </u>of the pole is 12 feet

Required

  • Length of the rope.

To get the length of the rope, you will use the pythagoras theorem expressed as:

  • c² = a² + b²

Substituting the given parameters:

c² = 9² + 12²

c² =81 + 144

c² = 225

c = √225

c = 15 feet

Therefore the length of the rope needed is 15 feet

Learn more on Pythagoras theorem here: brainly.com/question/231802

7 0
2 years ago
What is the common difference for the sequence shown below?
Nezavi [6.7K]

we can always find the slope of any line by simply using two points on the line, say let's  use (3,4) and (-1,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-4}{-1-3}\implies \cfrac{-2}{-4}\implies \stackrel{\stackrel{\textit{common difference}}{\downarrow }}{\cfrac{1}{2}}

5 0
3 years ago
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