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Paha777 [63]
3 years ago
15

U.S. cybersecurity experts and government officials are increasingly concerned about breaches from __________ into corporate net

works, either through mobile devices or by other means.
Computers and Technology
1 answer:
Triss [41]3 years ago
5 0

Answer:

Organized crime syndicates based in the United State

Explanation:

U.S. cybersecurity experts and government officials are increasingly concerned about breaches from organized crime syndicate based in the United States into corporate networks, either through mobile devices or by other means.

The crime syndicate can go to any length to access corporate network through mobile device or any other means in order to commit crimes that is why the US cyber security expert and government officials are increasingly concerned.

Cyber security specialists or expert in the US are been employed to protect information or data that the crime syndicate may want to gain access to by using different variety of techniques by critically monitoring the systems network for attempted breaches by the crime syndicates and then dealing with any of them that is found guilty.

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In the dental industry, light-activated adhesives have been used for decades to help adhere braces to teeth as well as being use
Bas_tet [7]

In the dental industry, light-activated adhesives have been used for decades to help adhere braces to teeth as well as being used in other dental procedures. These adhesives are one-part translucent polymers that cure and harden when exposed to specific light spectrum. Many of these took up to 30 seconds to cure. New technology brings LED blue light curing which uses blue LED with UV light to cure and harden a light-activated adhesive in 3-5 seconds. Which result below would NOT be an advantage of this new technology?<u> A)There is a higher up-front expense.</u> B)Could be used in other areas such as sealing cracked pipes. C)No filters or cooling fan required due to quick curing and low heat emission. D)There is a major time savings when using the faster high–intensity curing lights.

7 0
3 years ago
Read 2 more answers
What is the name of the top-level parentless folder in a digital file system?
Viefleur [7K]

Answer:

ROOT

Explanation:

6 0
3 years ago
You can use the Trim Video feature to specify a video file’s Start and End time in order to control which portion of the video f
mario62 [17]

Answer:

True

Explanation:

You can trim a video and actually set the start time and end time of a video on Powerpoint (a presentation software by microsoft) by following some simple steps.

select the video and click the playback tab, click the Trim video and a box will pop up, you can play the video and see how it is trimmed, and finally click OK.

5 0
3 years ago
Using the college registration example from section 6.7.3 as a starting point, do the following:
Arada [10]

Answer:

Explanation:

NCLUDE Irvine32.inc

TRUE = 1

FALSE = 0

.data

gradeAverage WORD ?

credits WORD ?

oKToRegister BYTE ?

str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0

main PROC

call CheckRegs

exit

main ENDP

CheckRegs PROC

push edx

mov OkToRegister,FALSE

; Check credits for valid range 1-30

cmp credits,1 ; credits < 1?

jb E1

cmp credits,30 ; credits > 30?

ja E1

jmp L1 ; credits are ok

; Display error message: credits out of range

E1:

mov edx,OFFSET str1

call WriteString

jmp L4

L1:

cmp gradeAverage,350 ; if gradeAverage > 350

jna L2

mov OkToRegister,TRUE ; OkToRegister = TRUE

jmp L4

L2:

cmp gradeAverage,250 ; elseif gradeAverage > 250

jna L3

cmp credits,16 ; && credits <= 16

jnbe L3

mov OkToRegister,TRUE ; OKToRegister = TRUE

jmp L4

L3:

cmp credits,12 ; elseif credits <= 12

ja L4

mov OkToRegister,TRUE ; OKToRegister = TRUE

L4:

pop edx ; endif

ret

CheckRegs ENDP

END main

8 0
4 years ago
assume for arithmetic, load/store, and branch instructions, a processor has CPIs of 1, 12, and 5, respectively. Also assume that
KonstantinChe [14]

Answer:

1 PROCESSOR :

(1 × 2.56 × 10^9) + (12 × 1.28 × 10^9) + (5 × 2.56 × 10^8) / 2 GHz = 9.6 s

2 PROCESSORS :

(1×2.56×10^9)+(12×1.28×10^9)/0.7×2 + (5 × 2.56 × 10^8) / 2 GHz = 7.04 s

Speed -up is 1.36

4 PROCESSORS :

(1×2.56×10^9)+(12×1.28×10^9)/0.7×4 + (5 × 2.56 × 10^8) / 2 GHz = 3.84 s

Speed -up is 2.5

5 PROCESSORS :

(1×2.56×10^9)+(12×1.28×10^9)/0.7×8 + (5 × 2.56 × 10^8) / 2 GHz = 2.24 s

Speed -up is 4.29

Explanation:  

The following formula is used in this answer:

EXECUTION TIME = CLOCK CYCLES / CLOCK RATE

Execution Time is equal to the clock cycle per clock rate

7 0
3 years ago
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