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Ganezh [65]
3 years ago
15

The domain of the following relation R {(6, −2), (1, 2), (−3, −4), (−3, 2)} is (1 point)

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

Domain: { -3,1,6}

Step-by-step explanation:

The domain is the input values

Domain: { 6,1,-3,-3}

We usually put them in numerical order and we do not list the same value twice

Domain: { -3,1,6}

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Write the sum of 5x2 + 2x - 10 and 2x2 + 6 as a polynomial in standard form.
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Answer:

7x^2+2x-4

Step-by-step explanation:

a standard form is ax+by=c

5x^2 add 2x^2=7x^2 then -2x but when you have a -10 +6 you get -4 giving you the answer of 7x^2 +2x -4

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4 drinks.

Step-by-step explanation:

-One drink is defined as having one-half ounce of pure ethyl alcohol; each of the following is considered "one drink." *1 oz of 100 proof distilled spirits at 50% alcohol.

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Find the length of the side of a square, given that the area of the square minus the length of a side is 812.
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Step-by-step explanation:

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In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

                                                                     are congruent

9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

4 0
3 years ago
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