Question

A rectangle has a height of 2x^42x 4 2, x, start superscript, 4, end superscript and a width of x^2+8x+15x 2 +8x+15x, squared, plus, 8, x, plus, 15.

Answer 1

Question:

A rectangle has a height of 2x^4 and a width of x^2+8x+15. Calculate its area.

Answer:

$Area = 2x^6 + 16x^5 + 30x^4$

Step-by-step explanation:

Given

$Height = 2x^4$

$Width = x^2 + 8x + 15$

Required

Determine the area of the rectangle

This is calculated as:

$Area = Width * Height$

$Area = (x^2 + 8x + 15) * 2x^4$

$Area = 2x^6 + 16x^5 + 30x^4$