Answer:
<h3>perpendicular line:
y = -¹/₆
x + 4¹/₃
</h3><h3> parallel line:
y = 6x - 45
</h3>
Step-by-step explanation:
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y = 6x - 7 ⇒ m₁=6
6×m₂ = -1 ⇒ m₂ = -¹/₆
The line y=-¹/₆
x+b passes through point (8, 3) so the equation:
3 = -¹/₆
×8 + b must be true
3 = -⁴/₃ + b
b = 4¹/₃
Therefore equation in slope-intercept form:
y = -¹/₆
x + 4¹/₃
y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂
{Two lines are parallel if their slopes are equal}
y = 6x - 7 ⇒ m₁=6 ⇒ m₂=6
The line y=6x+b passes through point (8, 3) so the equation:
3 = 6×8 + b must be true
3 = 48 + b
b = -45
Therefore equation in slope-intercept form:
y = 6x - 45
Find the GCF of 88 and 24 first
88=2*2*2*11
24=2*2*2*3
The GCF for 88 and 24 is 8
The GCF for r^18 and r^13 is r^13 (because they both contain r^13 in them)
=8r^13(11, 3)
Hope I helped :)
Answer:
(6, 9 ) and r = 3
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given
x² + y² - 12x - 18y + 108 = 0
Rearrange the x- terms and the y- terms together and subtract 108 from both sides, that is
x² - 12x + y² - 18y = - 108
To obtain standard form use the method of completing the square
add ( half the coefficient of the x and y terms )² to both sides
x² + 2(- 6)x + 36 + y² + 2(- 9)y + 81 = - 108 + 36 + 81
(x - 6)² + (y - 9)² = 9 ← in standard form
with centre = (6, 9 ) and r = = 3
Answer:
1 2/6 is the correct answer
Step-by-step explanation:
in 2 1/6 + -5/6 what you do is you can turn the plus sign into a minus sign and make -5/6 5/6 so now the problem is 2 1/6 - 5/6 and the awnser to that is 1 2/6
Answer:
ano hindi po ma hintindihan po hindi paano po yan masasagutan