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ANEK [815]
3 years ago
9

Hello please help i’ll give brainliest

Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

Ahimsa, it means 'non-injury' and 'non-killing'

Margarita [4]3 years ago
6 0
Ahisma
It means (in the Hindu, Buddhist, and Jainist tradition) respect for all living things and avoidance of violence toward others.
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1/2s=4s-21 I don't understand
Dimas [21]
\frac{1}{2} s = 4s - 21

First, simplify \frac{1}{2} s to \frac{s}{2} / Your problem should look like: \frac{s}{2} = 4s - 21
Second, multiply both sides by 2. / Your problem should look like: s = 8s - 42
Third, subtract 8s from both sides. / Your problem should look like: s - 8s = -42
Fourth, simplify s - 8s to -7s. / Your problem should look like: -7s = -42
Fifth, divide both sides by -7. / Your problem should look like: s =  \frac{-42}{-7}
Sixth, simplify \frac{42}{-7} to - \frac{42}{7} / Your problem should look like: s =  \frac{42}{7}
Seventh, simplify \frac{42}{7} to 6. / Your problem should look like: s = 6

Answer: s = 6

4 0
3 years ago
Which expression is equivalent to 9s + 3 x 5 -2s?
marissa [1.9K]
The answer is A. When you take the 9s and the -2s, you get 7s. Then you add the 3x5 and end up with 15. Giving you the answer 7s+15
6 0
2 years ago
Read 2 more answers
Select Proportional or Not Proportional to correctly classify each pair of ratios.
Paul [167]

Answer:

Not Proportional

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
Find the slope of the ordered pair. A(4,6) B(5,8)
andrezito [222]

Answer:

<h2>The slope is 2</h2>

Step-by-step explanation:

Step one:

we are required to find the slope of the given data points

A(4,6) B(5,8)

hence the x and y values correspond to

x1=4

y1=6

x2=5

y2=8

Step two:

Required is the slope which is

slope= y2-y1/x2-x1

Slope=8-6/5-4

Slope= 2/1

<em><u>Hence the slope of the ordered pair is 2</u></em>

3 0
3 years ago
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