Since it is perimeter, it is just meters, instead of being squared or cubed like with area and volume.
Answer:
26,812 ft
Step-by-step explanation:
The drawing given is very helpful in this case. When solving problems like this, it's important to realize what trigonometric ratio we're going to use. From the given angle (50°), we are given the hypotenuse (35,000 ft) and we're trying to solve for the opposite side ().
So since we're trying to find the opposite side side and we have the hypotenuse, we should try to find a trigonmetric ratio between the opposite side and the hypotenuse. Using SOH-CAH-TOA, hopefully you can see that we should pick SOH (i.e. ). Therefore, we can set up our equation given the angle .
Since we're solving for , we can just rearrange to get
Therefore, the plane's altitude is 26,812 ft.
Can't read it it's blurry. Sorry.
First find half of the perimeter of the triangle: s = (a + b + c) / 2 = 11.095
Then the area is:
A = Square Root [11.095 (11.095 - 7.7)(11.095 - 5.2)(11.095 - 9.29)] = 20.01999895 or 20.02 square feet rounded to 2 decimal places.
What’s the question ? Do I have to solve this?