d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
If You mean A sum to write here's one :
31+3
I think it is fifty-four hundred
Answer: x= 2.5, y = 10
Step-by-step explanation:
<u><em>I'm going to assume that these photocopies are proportional in relations to each other.</em></u>
If they're proportional, you can set up two proportions:

And cross-multiply:

Then solved for x and y:

Answer:
20 4/7 inches
Step-by-step explanation:
Take 12 feet and convert to inches
1 ft = 12 inches
12 * 12 = 144 inches
Divide by 7
144/7 =20 with 4 left over
20 4/7 inches