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marusya05 [52]
3 years ago
9

the Function h(x)=1/2(x+3)^2+2. How is the graph of h(x) translated from the parent graph of a qaudratic function, f(x)=x^2

Mathematics
2 answers:
Kay [80]3 years ago
6 0

Answer:

Translation of h(x) is 2 unit down, 3 unit right and vertical stretch by 2

Step-by-step explanation:

Given function: h(x)=\dfrac{1}{2}(x+3)^2+2

Parent function: f(x)=x^2

It is parabolic function.

h(x)=\dfrac{1}{2}(x+3)^2+2

Shift 2 unit down

g(x)=\dfrac{1}{2}(x+3)^2+2-2

g(x)=\dfrac{1}{2}(x+3)^2

Shift 3 unit right

g(x)=\dfrac{1}{2}(x+3-3)^2

g(x)=\dfrac{1}{2}x^2

Vertical stretch by factor 2

g(x)=2\cdot dfrac{1}{2}x^2

g(x)=x^2=f(x)

So, Translation of h(x) is 2 unit down, 3 unit right and vertical stretch by 2

Tresset [83]3 years ago
3 0

Answer:

i'm not sure sorry

Step-by-step explanation:

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Answer:

  vertex: (2, -3.2)

  axis of symmetry: x = 2

  zeros: x=0, x=4

  formula for axis of symmetry:

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Step-by-step explanation:

a) The vertex x-coordinate is halfway between the zeros, so is x = (0+4)/2 = 2. It is where the graph has a turning point.

The vertex y-coordinate is the low point of this graph. It is not on a grid line, so we can only guess at its value. I choose to call it -3.2.

The vertex is (2, -3.2).

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b) The axis of symmetry is the vertical line through the vertex. The constant in its equation is the x-coordinate of the vertex:

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c) The zeros of the function are where the function crosses the x-axis. These are marked on the graph with red dots. The zeros are x=0 and x=4.

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d) When the quadratic is written in standard form, ax^2 +bx +c, the equation of the axis of symmetry is ...

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Another is to average the zeros, since they are symmetrical about the axis of symmetry.

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If the quadratic is written in vertex form, the vertex coordinate is the constant in the equation for the axis of symmetry.

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  x = h . . . . . . equation of axis of symmetry

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