Please help me ! i'm bad @ math (::

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

I agree with sdarbeh once you multiply the answer will be 34.
Make his answer the brainliest

Elodia [21]3 years ago

3 0

The correct answer is 34

To solve first multiply whole number
2 times 16 = 32
Then you multiply the numerator in the fraction
1 times 16 =16
The answer is know 32 and 16/8
The last step is simplifying. 8 goes into 16 two times
So the final procedure is 32+2= 34

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3 years ago

What's the difference between 1 and 1 3/5

Dennis_Churaev [7]

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$